Topic: number as the extension of a class of equinumerous classes
Quotation Skeleton
Now it must be possible to prove, by … is equal to every other concept under which … which belongs to any such concept, and that … … we have to find a relation \phi which … an object which falls under G; and [vice versa] … it follows, on our assumption [that no object falls under either concept], that these …
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Topic: number as the extension of a class of equinumerous classes (23 items)